I think there's a lot of statements that can be made or argued. Many of you are just trying to take imperfections of today's representation of ideas (in this case, written math) and are representing them as logical insights when they are just failings of how we display perfect ideas with imperfect systems. Look at what I can do with the same logic that many of you impose:
ASSUMING:
Whereas, X is equal to the probability of selecting the integer of 42 out of all integers possible, in a perfectly and equally random environment. X has N probability out of infinity.
Whereas, Y is equal to every possibility of an appropriate integer that is not 42, and assuming that there are infinite integers possible. Y has every probability of infinity, save for one of them. (42)
Whereas,
∞ is equal to the coefficient or symbol of infinity, or infinite probabilities/possibilities. This means X and Y together must equal infinity.
Whereas N is equal to one possibility out of infinity, not necessarily but quite possibly 42. N and Y also equal infinity. X and N are equal in amount of probability in being selected out of infinity, as they both just represent a single integer in the random pool of integers ranging up to infinity. X however, is special and must only be 42. With me so far?
∞ - N = Y
∞ - X = Y
X = N
N + Y = ∞
X + Y = ∞
Y cannot equal infinity without X, if N is not present.
Y cannot equal infinity without N, if X is not present.
Therefore, N, and surely X as well, has significance to some sort of amount, or bearing, no matter how minimal.
To represent the very smallest amount in decimal, you must show a representation of an infinite amount of zeroes (0) before you show a representation of 1. This representation accurately shows what X's probability is.
(Spacer, the following underscore is to be above .000) ___
(As a decimal, total probability/possibility is 1) X = 0.000000001
From here on out, the variable P Is to be assumed as a representation of the decimal above.
X is not neutral, is not negative, but it is indeed positive.
1 > X > 0
P = X
1 > P > 0
1/∞ = P
1/∞ = X
X/∞ = (1/∞)/(∞)
None.