Lol I got pwnt D:
EDIT: I stand corrected.
You remain pwnt.
Holy crap terrain hall of fame.
None.
Although, you have to ask yourself, why did he crop the picture so small? Is he hiding the edges and their horrible blockiness?
None.
Although, you have to ask yourself, why did he crop the picture so small? Is he hiding the edges and their horrible blockiness?
Thats what i was thinking too. Most likely the case because i think once you do a blend like that it ruins the isom pattern.
None.
There's nothing outside but default dirt terrain. I just selected specific tiles and combined them. It took me less than fifteen seconds, regardless.
None.
Does it have to go somewhere?
"Parliamentary inquiry, Mr. Chairman - do we have to call the Gentleman a gentleman if he's not one?"
That one looks really bad.
I think rockz technically wins because I could see that being a tiny walkway into that temple structure.
It also turned out to be a pretty good cliff doodad too.
"Parliamentary inquiry, Mr. Chairman - do we have to call the Gentleman a gentleman if he's not one?"
Better?
The bridge tile itself doesn't fit.
Please report errors in the Staredit.Network forum.
ALL PRAISE YOUR SUPREME LORD CORBO
I think rockz technically wins because I could see that being a tiny walkway into that temple structure.
I think so too, but as far as for a
working short bridge, mine wins
fuck you all
This may be the blockiest / longest of all bridges shown, also my first time trying to make (blend) a bridge:
This may be small, but very blocky inbetween bridges
Post has been edited 1 time(s), last time on Aug 13 2009, 8:11 pm by NothingZ.
None.
Actually Inferno, it CAN get smaller than that by diagonals
Actually, applying the Pythagorean theorem, it's longer with diagonals. Remember In this case, it would be 1+1=2, and the square root of two is radical 2. Using a calculator, that rounds to 1.4. 1.4 > 1.
Actually if the pieces existed it could get smaller than that by diagonals. Your math is correct but the answer you were looking for (the area) is not the answer this formula finds. a
2+b
2=c
2 is used to determine the length of the side of a right triangle and in this case the hypotenuse(term used when for the longest side opsite a 90degree angle on a triangle).
so technically if the two right triangles making up this square were arranged to form a parrelogram they would have the exact same area as the square. To get a smaller area the hypotenuse must be smaller than square root of two. so two right triangles with a hypotenuse length of one would suffice as each one of their sides would be less than 1 and thus yield a total area of less than 1.
None.