None.
Just go ahead and post it Unholy, I don't have a good one at the moment.
Heheheheh okay 
There are Twelve Balls and a Balance.
One ball out of the twelve is either Lighter or Heavier than the rest. You do NOT know if it's lighter or heavier...
Using the balance only THREE times.. Determine what way(s) to use the balance in order to figure out which ball is the odd one, and whether it's lighter or heavier. Note that you must consider ALL possible scenarios, and that you must still be able to find the ball in all scenarios.
I've done this.. and I found an answer... My friend also did it and found another answer.. we both took about a day...
There are Twelve Balls and a Balance.
One ball out of the twelve is either Lighter or Heavier than the rest. You do NOT know if it's lighter or heavier...
Using the balance only THREE times.. Determine what way(s) to use the balance in order to figure out which ball is the odd one, and whether it's lighter or heavier. Note that you must consider ALL possible scenarios, and that you must still be able to find the ball in all scenarios.
I've done this.. and I found an answer... My friend also did it and found another answer.. we both took about a day
...None.
Are we allowed to use anything besides the balance? Do the balls all look the same, are the same size, ect?
If so, this is a tough one. With three tries, binary selection isn't going to work (2^3 is only 8). My first thought was to only 6 on the scales, if the scales change, you know its in those 6, if it doesn't you know it's in the other 6. Then put 4 on, if it stays the same you know its one of the other two, if they change you know it's one of the pairs on there. If it was the pair not on the scales, then you can put a "normal" ball on the scales with one of the two that you've narrowed it down to, and that will tell you which was the ball you're looking for, but as you can see this won't work.
My second thought is to break it into 8 and 4, which might have a shot. (kinda thinking as I type here) If we put 8 balls on and they balance, we know its one of the remaining 4. Then we could just swap 3 of the remaining 4 onto one of the sides, if they balance, we know the last one is the odd ball and can balance it against a normal ball, if they don't balance, we know we either have a heavier ball or a lighter ball and the 3 that it is in. We can then take 2 of the three and balance them, if they're unequal, we have our ball, and if they're equal, the 3rd is our ball.
If the 8 balls dont balance..... hmmm
One side either contains a heavier ball or a lighter ball, so... we ....(pause for thinking lol)
Swap out 3 of the balls on one of the sides out with 3 of the non-odd-balls, and swap the remaining one on that side with one on the other side. If the scales balance, then you know that your ball is in the 3 you removed, and you can clear off all the balls, pick 2 of your 3 that you know its in. If that balances, you know yours was the 3rd and from the inital balance you know it is either heavier or lighter depending on which side it was on. If it doesn't balance, well, you still know you're looking for either the heavier or the lighter one from the initial balance, and the heavier or lighter one in this balance will be your ball.
If the scales after the swap didn't balance, they either stayed the same, or switched balances. If they stayed the same, then the ball was one of the 3 you put on. Based on which side (heavier/lighter) you swapped the balls onto, you can tell that your ball in the 3 you swapped on was heavier/lighter corresponding to that, so pick 2 of the 3 and if they balance, the last one is your ball and is heavier/lighter depending on the previous balance, and if they don't balance you know which one is heavier/lighter already so can just pick that one of the two you balanced. If the scales switched balances after the swap, you know your ball was one of the two you switched sides on during the swap, since there is only 1 heavier/lighter ball and if it was on the opposite side to begin with, the only way for the scales to switch up/down would be for you to switch it to the other side. You then know whether the ball you're looking for is heavier/lighter, and can just balance out the two you had switched sides to find the one you wanted.
I think that's it! Better Check though
8/balance/
If so, this is a tough one. With three tries, binary selection isn't going to work (2^3 is only 8). My first thought was to only 6 on the scales, if the scales change, you know its in those 6, if it doesn't you know it's in the other 6. Then put 4 on, if it stays the same you know its one of the other two, if they change you know it's one of the pairs on there. If it was the pair not on the scales, then you can put a "normal" ball on the scales with one of the two that you've narrowed it down to, and that will tell you which was the ball you're looking for, but as you can see this won't work.
My second thought is to break it into 8 and 4, which might have a shot. (kinda thinking as I type here) If we put 8 balls on and they balance, we know its one of the remaining 4. Then we could just swap 3 of the remaining 4 onto one of the sides, if they balance, we know the last one is the odd ball and can balance it against a normal ball, if they don't balance, we know we either have a heavier ball or a lighter ball and the 3 that it is in. We can then take 2 of the three and balance them, if they're unequal, we have our ball, and if they're equal, the 3rd is our ball.
If the 8 balls dont balance..... hmmm
One side either contains a heavier ball or a lighter ball, so... we ....(pause for thinking lol)
Swap out 3 of the balls on one of the sides out with 3 of the non-odd-balls, and swap the remaining one on that side with one on the other side. If the scales balance, then you know that your ball is in the 3 you removed, and you can clear off all the balls, pick 2 of your 3 that you know its in. If that balances, you know yours was the 3rd and from the inital balance you know it is either heavier or lighter depending on which side it was on. If it doesn't balance, well, you still know you're looking for either the heavier or the lighter one from the initial balance, and the heavier or lighter one in this balance will be your ball.
If the scales after the swap didn't balance, they either stayed the same, or switched balances. If they stayed the same, then the ball was one of the 3 you put on. Based on which side (heavier/lighter) you swapped the balls onto, you can tell that your ball in the 3 you swapped on was heavier/lighter corresponding to that, so pick 2 of the 3 and if they balance, the last one is your ball and is heavier/lighter depending on the previous balance, and if they don't balance you know which one is heavier/lighter already so can just pick that one of the two you balanced. If the scales switched balances after the swap, you know your ball was one of the two you switched sides on during the swap, since there is only 1 heavier/lighter ball and if it was on the opposite side to begin with, the only way for the scales to switch up/down would be for you to switch it to the other side. You then know whether the ball you're looking for is heavier/lighter, and can just balance out the two you had switched sides to find the one you wanted.
I think that's it! Better Check though
8/balance/
None.
I think there is something wrong with your second step
"One side either contains a heavier ball or a lighter ball, so... we ....(pause for thinking lol)
Swap out 3 of the balls on one of the sides out with 3 of the non-odd-balls, and swap the remaining one on that side with one on the other side." ..
Let's say after your first weighing that 1 of the 4 balls on the Left side is heavier OR 1 of the 4 balls on the Right side is Lighter ...
We swap 3 of the Lighter ones out with Non-odd balls.... and then Swap the remaining May-be-Lighter ball with a May-be-Heavier ball.. (is this what you're saying?)
In that case, if the Left side remain heavy... you won't know whether it's the May-be-Lighter ball that you switched, or the 3 may-be-heavier balls that you left there...
If this isn't wat you said.. correct me.. because you're an inch away from the answer
"One side either contains a heavier ball or a lighter ball, so... we ....(pause for thinking lol)
Swap out 3 of the balls on one of the sides out with 3 of the non-odd-balls, and swap the remaining one on that side with one on the other side." ..
Let's say after your first weighing that 1 of the 4 balls on the Left side is heavier OR 1 of the 4 balls on the Right side is Lighter ...
We swap 3 of the Lighter ones out with Non-odd balls.... and then Swap the remaining May-be-Lighter ball with a May-be-Heavier ball.. (is this what you're saying?)
In that case, if the Left side remain heavy... you won't know whether it's the May-be-Lighter ball that you switched, or the 3 may-be-heavier balls that you left there...
If this isn't wat you said.. correct me.. because you're an inch away from the answer
None.
Quote from 
UnholyUrine
UnholyUrineIn that case, if the Left side remain heavy... you won't know whether it's the May-be-Lighter ball that you switched, or the 3 may-be-heavier balls that you left there...
Left side: A B C D (heavy)
right side: E F G H (light)
not-on-scale: K K K K
Since it didn't balance, we know the 4 K's aren't our ball, so we do this:
Left side: E B C D (Heavy)
Right side: A K K K (Light)
not-on-scale: F G H K
Since the Left side is still heavy, our ball can't be A or E because they were on opposite sides before the switch, and it can't be the K's since they're normal balls, so it has to be B C or D which is heavy. Then we can just compare B and C, C and D, or D and B. If B and C are equal, then D is our heavy ball. If they're not equal, the heavy one is our heavy ball.
None.
Moves without legs.
Lifespan has two eggs.
Digs without claws.
Drools from it's maws.
Lifespan has two eggs.
Digs without claws.
Drools from it's maws.
None.
a worm?
None.
No.
2/4
It does move without legs.
It does dig without claws, but worms have no maws, and they don't have two eggs in their life cycle.
2/4
It does move without legs.
It does dig without claws, but worms have no maws, and they don't have two eggs in their life cycle.
None.
Quote
After the 1st weigh in the below configuration, they didn't balance.
Left side: A B C D (heavy)
right side: E F G H (light)
not-on-scale: K K K K
Since it didn't balance, we know the 4 K's aren't our ball, so we do this:
Left side: E B C D (Heavy)
Right side: A K K K (Light)
not-on-scale: F G H K
Since the Left side is still heavy, our ball can't be A or E because they were on opposite sides before the switch, and it can't be the K's since they're normal balls, so it has to be B C or D which is heavy. Then we can just compare B and C, C and D, or D and B. If B and C are equal, then D is our heavy ball. If they're not equal, the heavy one is our heavy ball.
Left side: A B C D (heavy)
right side: E F G H (light)
not-on-scale: K K K K
Since it didn't balance, we know the 4 K's aren't our ball, so we do this:
Left side: E B C D (Heavy)
Right side: A K K K (Light)
not-on-scale: F G H K
Since the Left side is still heavy, our ball can't be A or E because they were on opposite sides before the switch, and it can't be the K's since they're normal balls, so it has to be B C or D which is heavy. Then we can just compare B and C, C and D, or D and B. If B and C are equal, then D is our heavy ball. If they're not equal, the heavy one is our heavy ball.
Hmm I think you got it
... Nice StuffEDIT:
I'm guessing Slugs!! .. altho they don't have life cycle of 2 eggs i think?
Post has been edited 1 time(s), last time on Jun 24 2009, 5:45 pm by UnholyUrine.
None.
Quote from candle12345
Moves without legs.
Lifespan has two eggs.
Digs without claws.
Drools from it's maws.
Lifespan has two eggs.
Digs without claws.
Drools from it's maws.
A sea turtle.
They have flippers, not legs.
They life to be over 100, 00 = 2 eggs.
The lay eggs by digging into the beach with their flippers.
They... Have a maw.
None.
If the 100 . 00 = 2 eggs turns out to be right.. I'd rip out the testicles of the guy who thought of this lame riddle :\
None.
No, 100,000 does not equal 2.
Glad to see the mathematicians here are brilliant.
The term maw in this case refers to the jaws of a predator.
Two more guesses and I'll reveal it.
Unless you start getting closer.
Post has been edited 1 time(s), last time on Jun 25 2009, 3:06 am by candle12345.
Glad to see the mathematicians here are brilliant.
The term maw in this case refers to the jaws of a predator.
Two more guesses and I'll reveal it.
Unless you start getting closer.
Post has been edited 1 time(s), last time on Jun 25 2009, 3:06 am by candle12345.
None.
I was saying that two 0s next to each other resemble 2 eggs. (And 0 is sometimes referred to as in french as an egg.)
FIne, I'll guess again.
MAN.
FIne, I'll guess again.
MAN.
None.
how does MAN fulfill the moves without legs part? Yeah we have cars and planes and stuff but, we still do a lot of walking
None.
Quote from 
Vrael
Vraelhow does MAN fulfill the moves without legs part? Yeah we have cars and planes and stuff but, we still do a lot of walking
Moving with legs doesn't preclude moving without legs.
None.
Some sort of snake perhaps?
None.
Is the thing actually allive? 
None.
Quote from candle12345
Moves without legs.
Lifespan has two eggs.
Digs without claws.
Drools from it's maws.
Lifespan has two eggs.
Digs without claws.
Drools from it's maws.
A hydralisk?
or a nydus worm?
None.
He never said it had to be an animal...
Is it a robot?
Is it a robot?
None.
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