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[2014-9-23. : 3:41 am]  O)FaRTy1billion[MM] -- I did them manually... a0 b1 c1 d0 | 0 , (C xor (B and D)) xor A == (1 xor (1 and 0)) xor 0 == (1 xor (0)) xor 0 == (1) xor 0 == 1, but it should be 0 ;o[2014-9-23. : 3:41 am]  Jack -- now you have (p v q) & (p v q) which is the same as A&A which is the same as just A[2014-9-23. : 3:40 am] Jack -- so just get rid of B (aka your original R) because it never affects the result[2014-9-23. : 3:40 am] Jack -- see, if A or B has to be true at the same time as A or notB for the expression to be true, then let's say A is 0 and B is 1. The expression will never be B, because it will be like (0 v 1) & (0 v 0), which is not going to work.[2014-9-23. : 3:39 am] Zoan -- well the long expression not the end there is displaying the correct 1's and 0's[2014-9-23. : 3:38 am] O)FaRTy1billion[MM] -- dug out my old laptop ... I'd install the program on this computer, but it is one of those softwares that, upon installtion, assumes that is now the sole purpose of that machine and loads so much stuff at startup ;o[2014-9-23. : 3:36 am] Jack -- Dem0n first look at (p v q v r) & (p v q v ~r), you can think of this as being (A v B) & (A v ~B)[2014-9-23. : 3:35 am]  jjf28 -- the already do if/else, recursive definitions, and function definitions, but it's like they resist all the cool conditionals/branching[2014-9-23. : 3:35 am] O)FaRTy1billion[MM] -- I should just dig out my old laptop which still has the circuit software for defining logic expressions/circuits out of truth tables .. I can't seem to find such utility by googling for it[2014-9-23. : 3:33 am] jjf28 -- copbonercopboner shouted: math is 4 dum nerdz lmao Kill him! Kill the traitor![2014-9-23. : 3:33 am] MasterJohnny -- its more like cs stuff than math...i wish i could use XOR in math...[2014-9-23. : 3:32 am] O)FaRTy1billion[MM] -- because if I do "(C xor (B and D)) xor A", I get too many 1s in my truth table.[2014-9-23. : 3:31 am] Zoan -- but usually people just put things in parenthesis, I dunno why they wouldn't[2014-9-23. : 3:30 am] Zoan -- Actually, I think in logic I think the only order is determined by parenthesis[2014-9-23. : 3:30 am] jjf28 -- there are algebraic ways of doing it, usually you complicate something with not-nots till de-morgans starts working[2014-9-23. : 3:29 am] jjf28 -- that's the kind of insane expression that i'd just truth table and reverse engineer[2014-9-23. : 3:28 am] O)FaRTy1billion[MM] -- is it (C xor B) and (D xor A), ((C xor B) and D) xor A, (C xor (B and D)) xor A ? |
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