I forgot to mention that the equal sign is the one with three lines -- apparently that means 'The same as'
...what?
It actually means "Is defined to be".
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You might of given us something wrong, which is why we keep getting
x - 6 = x + 6. I'm guessing the left side is supposed to be
x - 6, not
x + 6.
If everything is correct then then the left is not defined to be the right. My proof:
None.
Let's have a math challenge every week.
None.
Let's have a math challenge every week.
I second this motion! Lets do calculus!
I am a Mathematician
((x - 3) / x) - ((x - 2) / (x+2)) = ((x + 6) / (x (x +2)))
x-3 x-2 x+6 x != -2 and 0
---- - ----- = -----
x x+2 x(x+2)
(x+2)(x-3) - x(x-2) x+6
----------------------- = -----
x(x+2) x(x+2)
x^2-3x+2x-6 - x^2+2x x+6
--------------------------- = ------
x(x+2) x(x+2)
x-6 x+6
------- = ------
x(x+2) x(x+2)
x-6 = x+6
-6 = 6
There is no solution? Oo
Edit: I'm quite certain that if we wanted to get a solution, it should be either (x+3) in the 1st one of (x+2) in the second one...
None.
((x - 3) / x) - ((x - 2) / (x+2)) = ((x + 6) / (x (x +2)))
x-3 x-2 x+6 x != -2 and 0
---- - ----- = -----
x x+2 x(x+2)
(x+2)(x-3) - x(x-2) x+6
----------------------- = -----
x(x+2) x(x+2)
x^2-3x+2x-6 - x^2+2x x+6
--------------------------- = ------
x(x+2) x(x+2)
x-6 x+6
------- = ------
x(x+2) x(x+2)
x-6 = x+6
-6 = 6
There is no solution? Oo
Edit: I'm quite certain that if we wanted to get a solution, it should be either (x+3) in the 1st one of (x+2) in the second one...
There can't be no solution because it isn't an equation to begin with. All that can be said is that the left expression is not defined to be the right lol.
@ math contest: No fuck you.
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@ math contest: No fuck you.
Lawl. I'll take that as a yes.
None.
Let's have a math challenge every week.
I tried that in the Null a long time ago. It died out.
None.
Let's do it again. I'll win.
None.
Let's have a math challenge every week.
I second this motion! Lets do calculus!
I third this notion... But make it Applied Physics.
None.