0 / 0, what do you get?
You solve for it by solving it as x approaches 0 from the left, and from the right. If the two answers are equal, then you can say that the limit where x=0 is the answer. I taught myself calculus in high school.
y = lim (x->0) (1 / x)
1 / -0.0001 = -10000
1 / 0.0001 = 10000
-10000 ≠ 10000
y = 1 / x
(-infinity, 0) & (0, infinity)
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Post #13 Lord Agamemnon Jul 1 2008, 12:53 am
It depends on what you're doing with it. For instance, in the equation (X^2/X), at X=0 the value is 0 if you take the limit. In sin(x)/x, however, the limit is 1. 0/0 by itself is undefined; it depends on what function and context it's being used in.
Imaginary numbers aren't involved. Just calculus
0 represents nothing. Simply therefore you cannot divide something by 0 because you aren't dividing by anything. 0 -diviby- 0 = 0. So if you don't get it... You have nothing, you divide by nothing <-thats important. So your dividing by nothing (same thing as not dividing) leaving you with the original value unaffected. Nothing, which is 0.
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