I think this is something ridiculously simple but it just slipped out of my mind. Say you are given an equation: 0.0036 = p(1-cos(0.6/p)) how would you solve for p (note: cos is measured in radians, not degrees)? The answer given is p = 50, but can someone show me the steps?

I think this is something ridiculously simple but it just slipped out of my mind.

Say you are given an equation:
0.0036 = p(1-cos(0.6/p))

how would you solve for p (note: cos is measured in radians, not degrees)? The answer given is p = 50, but can someone show me the steps?

The book is wrong, by a factor of ten.

The book is wrong, by a factor of ten.

This is all I could get: 0.036 = p(1-cos(0.6/p)) 0 = p(1-cos(0.6/p)) - 0.036 0 = p - pcos(0.6/p) - 0.036 cos(nx) = 2 cos([n-1]x)cos(x) - cos([n-2]x) 0.6/p = 3/5/p = 3/5p = 6/10p = 1.2/2p = 3/5 * 1/p 3/5/p = 3/p/5

This is all I could get:

0.036 = p(1-cos(0.6/p))
0 = p(1-cos(0.6/p)) - 0.036
0 = p - pcos(0.6/p) - 0.036

cos(nx) = 2 cos([n-1]x)cos(x) - cos([n-2]x)

0.6/p = 3/5/p = 3/5p = 6/10p = 1.2/2p = 3/5 * 1/p

3/5/p = 3/p/5

[quote=name:Rantent]The book is wrong, by a factor of ten.[/quote] LOL oops, i meant 0.0036, not 0.036 mb

Quote from Rantent

The book is wrong, by a factor of ten.

LOL oops, i meant 0.0036, not 0.036 mb

[color=#b5b5ff]I [i]hate[/i] algebra..[/color]

I hate algebra..

Expand to Taylor series and approximate. :D

Expand to Taylor series and approximate.

[color=#b5b5ff]Win :p[/color]

Win

[quote=name:MillenniumArmy]I think this is something ridiculously simple but it just slipped out of my mind. Say you are given an equation: 0.0036 = p(1-cos(0.6/p)) how would you solve for p (note: cos is measured in radians, not degrees)? The answer given is p = 50, but can someone show me the steps?[/quote] You cannot really solve that, the solution is probably irrational. But you can approximate it by several methods, including Taylor series.

Quote from MillenniumArmy

I think this is something ridiculously simple but it just slipped out of my mind.

Say you are given an equation:
0.0036 = p(1-cos(0.6/p))

how would you solve for p (note: cos is measured in radians, not degrees)? The answer given is p = 50, but can someone show me the steps?

You cannot really solve that, the solution is probably irrational. But you can approximate it by several methods, including Taylor series.